Holland Bloorview Interview Questions, Process, and Tips

answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x​+602​) hrs and
Time needed to reach the station at 4 km/hr = (4x​+602​) hrs But 3x​+301​=4x​−301​⇒3x​−4x​=−302​=151​
⇒124x−3x​=151​⇒12x​=151​⇒x=1512​=54​ km

pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240

sow

1 : 2

5 * 6 * 7 = 210 ,
Two Least No’s are 5,6
There fore 5+6=11 is answer

The first 10 odd prime numbers are 3, 5, 7, 11, 13, 17, 19, 23, 29 and 31.

Sum of the odd prime numbers = (3+5+7+11+13+17+19+23+29+31)

= 158

Number of odd prime numbers = 10

We know, Average = (sum of the 10 odd prime numbers ÷ Number of odd

prime numbers)

Average =

= 15.8

∴ The Average of first 10 prime numbers which are odd is 15.8

no combinations is there because a number divisible by 36
also divisible by its divisors anu.sum of 4 digits=20,whis
is not multiple of 3.so it is cannot divisible by 3

Example 1:
Assign, A=20, B=10, C=5, D=5(Because C is equal to D as
given), E=1.
A/B = 20/10 = 2. So A/B = 2
A/C = 20/5 = 4. So A/C = 4
A/E = 20/1 = 20. So A/E = 20
Therefore “A/E is Greatest”
Example 2:
Assign, A=100, B=50, C=20, D=20(Because C is equal to D as
given), E=10.
A/B = 100/50 = 2. So A/B = 2
A/C = 100/20 = 5. So A/C = 5
A/E = 100/10 = 10. So A/E = 10
Therefore “A/E is Greatest”

original cost is 100^2 / (100^2 – p^2) Rs

Barber

speed=mile/hour
.•. time taken to travel M miles is

So, time =distance/speed
=M/m/h
=Mh/m hrs

10C3 = 120

5m/sec