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Ans is 25
s=36kmph
in meter per second is=36*5/18=>10
C. Rs. 6000
Joe is fencing in a square area of 576 square feet.
Fence posts, which are needed every three feet, cost 32.00 each.
The fencing cost 4.50 per foot. What is the total cost of the fencing materials?
Solution:-
Area of Square is 576 sq ft.
so, the length of side = root(576) = 24 ft
Since the fencing would be done on the perimeter, we would need that
formula is 4*side = 96 ft.
Number of Fence post needed = 96/3 = 32
1 Fence post cost = 32
32 Fence Post cost = 32 * 32 = 1024
Fencing cost = Perimeter * fencing cost = 96 * 4.5 = 432
Total Cost = 432 + 1024 = 1456
23
time (dist covrd by husband) (dist covrd by wife)
0.5hr 20 miles 0 miles
1 hr 40 miles 25 miles
1.5 hr 60 miles 50 miles
2 hrs 80 miles 75 miles
2.5 hrs 100 miles 100 miles
Therefore wife catches up after 2.5 hrs..
24kmph
time taken = x/40 + 2x/20
=> x=8
so, 3x = 24
Monday =y cheques
Tuesday =3y cheques
wednesday=4000 cheques
totaling to 16000 cheques
therefore y+3y+4000=16000 cheques
4y+4000=16000 cheques therefore 4y=16000-4000 cheques= 4y=12000cheques
therefore y=12000/4=3000 cheques
monday=3000 cheques
tuesday=3×3000=9000cheques
A certain sum amounts to Rs. 1725 in 3 years
and amounts to Rs.1875 in 5 years
so interest of 2 years = 1875 -1725
= 150
so interest of 1 year = 75
so interest of 3 years = 75 × 3 =225 rs
so , Principal = Amount – SI
= 1725 – 225
= 1500 rs
now ,
S.I. = P × N × R /100
75 = 1500 × 1 × R /100
R = 75 / 15
R = 5%
ans is C.
let H be present age of husaband.W be present age of wife.
H+W=91.
now let diff between their ages be x.that is H-W=x.
now when husband is W yaers old, his wife must be W-x years
old.and it is given that H=2(W-x). so 2W-H=2x. and H-
W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse
two H=52 W=39.
(d) none of these.
P+C+M=80
P+C=70
Therefore M=10
Given , P+M=90
If M=10
P=80
63:45:55
3 groups