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I WOULD STRIVE TO MAKE THE GOOGLE SEARCH MORE RESPONSIVE
TOWARDS THE QUESTIONS, AS THE GOOGLE RESULT JUST CONTAIN
THE SITE RELATED TO THE TERMS INCLUDED.
45(deg) 31' 4.3"
THEN WHAT WILL BE THE DEGREE WHEN TIME IS 3 O CLOCK
90 degree
12
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.
The work done by A in 8 days is = 8/ 12 = 2/3
Means A alone completes 2/3 part of work.
Remaining work which is (1–2/3) = 1/3 is completed by B in 8–2 = 6 days
So the complete work done by B in 6/(1/3) = 18 days.
B alone can complete the work in 18 days.
68 is the least number when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20
20
10*(root 2)
1 km/hr
.
860