Ques:- In a class 80% have passed english,70% passed Hindi 10% didnot passed either. If 144 students passed both. What is the total strength of the class.
Recent Answer : Added by Admin On 2020-05-17 12:01:21:
let t = total no of students.. then
students who passed one or both subjects,
n(e U h) = n(e) + n(h) – n(e intersection h)
=> t = 0.8t + 0.7t – 144
=> t = 1.5t – 144
students who failed both subjects is 10% i.e. 0.1t
=>t-n(e U h) = 0.1t,
=>t -(1.5t – 144) = 0.1t
=>t- 1.5t- 0.1t = -144
=> -0.6t = -144
=>t = 240
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Ques:- if a number is choosen between 100 and 999 includeing these numberrs what is the provbabilty that the number selected does not contain a 7 is
Recent Answer : Added by Admin On 2020-05-17 11:59:52:
p = prob(1st digit not 7)*prob(2nd digit not 7)*prob(3rd
digit not 7)
=(8/9)*(9/10)*(9/10)
=0.72
Sandhya had it right except that there are 900 numbers
between 100 and 999 inclusive (not 899).
Ques:- How many such pairs of letters are there in the word STAINLESS each of which has as many letters between them in the word as they have in the English alphabet, in the same sequence?
Recent Answer : Added by Admin On 2020-05-17 12:03:44:
Dear friends i ofcourse confused like you when i come
across to solve this problem. Really friends its very
simple if you understand the question clearly. First thing
is what is mean by “as many as” means its called ‘idiom and
phrase’ in english and it means “the same number of”. now
read the question “how many pairs of letters in STAINLESS
which has same number of letters between them in the word
as they have in english alphabet”.
In the alphabetical order, A-Z can be numbered as 1-26.
In A(INL)E which is same as in the alphabetical order A
(BCD)E. In both the cases E is in the Fourth position. so
we got one pair.
And in ST, there are no letters between them in the word
stainless. In alphabetical orer from A-Z also there is no
letters between them..so we got the second pair…
In STAINLESS it has two pairs ST and AE
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Ques:- GENUINE opposite?
Recent Answer : Added by Admin On 2020-05-17 12:01:11:
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Ques:- A worker earns a 5% raise. A year later, the worker receives a 2.5% cut in pay, & now his salary is Rs.22702.68
What was his salary to begin with?
Recent Answer : Added by Admin On 2020-05-17 12:01:03:
Assume his salary was Rs. X
He earns 5% raise. So his salary is (105*X)/100
A year later he receives 2.5% cut.
So his salary is ((105*X)/100)*(97.5/100)
which is Rs. 22702.68
So Ans is Rs.22176
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Recent Answer : Added by Chinnepalli Rajesh On 2020-12-23 16:10:25:
1/24S
Ques:- The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
Recent Answer : Added by Atif On 2022-12-05 16:13:26:
3600
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Ques:- A person is prisoned for 60 days . In that 60 days he earns rs.170.If he works he will get payed Rs.7 per day. If he doesn’t work Rs.3 he should pay to that prison.Find out how many days he worked.
Recent Answer : Added by ANCHAL PHUTELA On 2021-07-21 15:24:44:
He will work for 35 days in 60 days to earn Rs.170 as per the condition
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Ques:- A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream
Recent Answer : Added by Jay On 2022-05-17 09:07:04:
Ques:- 19 boys turn out for hockey. Of these, 11 are wearing hockey shirts and 14 are wearing hockey pants. There are no boys without one or the other. The number of boys wearing full uniform is
Recent Answer : Added by Admin On 2020-05-17 12:03:17:
( C ) 6
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Recent Answer : Added by Eyang, Daniel Eyoh On 2022-08-24 17:03:24:
15km/hr
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let t = total no of students.. then
students who passed one or both subjects,
n(e U h) = n(e) + n(h) – n(e intersection h)
=> t = 0.8t + 0.7t – 144
=> t = 1.5t – 144
students who failed both subjects is 10% i.e. 0.1t
=>t-n(e U h) = 0.1t,
=>t -(1.5t – 144) = 0.1t
=>t- 1.5t- 0.1t = -144
=> -0.6t = -144
=>t = 240