Bluetooth sig Interview Questions, Process, and Tips

324

the sum of all = 10
Accept
324 = 3+2+4 =/=10 (NOT EQUAL TO 10)

Dice

answer 10

D

FYI

ans: A/2
u get a diamond shape when u join those mid points
consider the 4 unshaded triangles
and u can form 2 square
when u analyse the squares u will get the answer

(c)UW

A. Rs. 8000, Rs. 7500, Rs. 3500

The answer for this question is very simple: it is called Ceaser Cipher.
It consists of replacing a character by another located in (current character position + (key-1)), where key = how many positions you want to skip.
For Example: VICTORY -> YLFWRUB with the key = 3.
Then SUCCESS -> QXFFHQQ

Note: it should work like a circle(Z+1 = A).

1/10 + 1/12 -1/20 = 15/2 i.e 7.5 h means 7 h & 30 min

24 Kmp/h

Yes, technology give me better efficiency to my work. Just we have take a work piece of sheet metal to convert in product like is box, different size, where manually it’s complete on 3 to 4 days but with the help of technology I have done in 3 hours that’s I said the technology give better efficiency to my better work.

( c ) 10

4. Annie Besant

– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.

– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m

To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec

In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m

at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m

If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)

Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.

For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.

This will take an additional (9.6 + 2) seconds.

Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds