Let the total rotations be x:
So the distance covered by both the wheels will be same,
9 * x = 7 * (x + 10)
x = 35 rotations
distance travelled = 9 * 35 = 7 * (35 + 10) = 315 feet
Violet
3.1
30
Prosperity for all
= 100 + 100 = 200 m
Time taken by train = 10 sec.
∵ Speed = Distance/Time
⇒ Speed of train = 200/10 = 20 m/sec.
∴ Speed of train = 20 × 18/5 = 72 kmph.
In question they left 10 seconds
answer
R-R*d/100-5(1-d/100)
1:2
Answer:
11 days.
Step-by-step explanation:
In the question,
Time taken by Ramesh to finish a piece of work = 20 days
Time taken by Sushil to finish a work = 25 days
Time for which they worked together = 5 days
Sushil left after = 5 days
So,
One day work of Ramesh is,
One day work of Sushil is,
So,
Work done in 5 days is given by,
Therefore, Remaining work is given by,
Now, as the Sushil left the remaining work was done by Ramesh,
Time taken by Ramesh for the remaining work is,
Therefore, the remaining work will be completed in 11 days by Ramesh.
GIVEN
80 CARDS IN 30 MINUTES.
Have to prove 7:30 ?
14 * 80 +80.
Answer is =1200.
To determine how many consecutive zeros the product of S will end with, we need to find the highest power of 10 that divides the product. This is equivalent to finding the highest power of 5 that divides the product, since the number of factors of 2 will always be greater than the number of factors of 5.
The primes in S are {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}.
There are 24 primes in S, so the product of S is:
2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 x 37 x 41 x 43 x 47 x 53 x 59 x 61 x 67 x 71 x 73 x 79 x 83 x 89 x 97
We need to find the highest power of 5 that divides this product. To do this, we count the number of factors of 5 in the prime factorization of each number in S.
5 appears once: 5
5 appears once: 25
5 appears once: 35
5 appears once: 55
5 appears once: 65
5 appears once: 85
So, there are six factors of 5 in the product of S. However, we also need to consider the powers of 5 that arise from the factors 25, 35, 55, and 65.
25 = 5 x 5 appears once: 25
35 = 5 x 7 appears once: 35
55 = 5 x 11 appears once: 55
65 = 5 x 13 appears once: 65
Each of these numbers contributes an additional factor of 5 to the product of S. Therefore, there are 6 + 4 = 10 factors of 5 in the product of S.
Since each factor of 5 corresponds to a factor of 10, we know that the product of S will end with 10 zeros. Therefore, the product of S will end with 10 consecutive zeros
Let the age of the man be x
Then age of his son becomes (x−24)
2 years later from now,
Age of man will be = x+2
and age of his son will be =(x−24+2)=x−22
According to question,
2(x−22)=x+2
i.e., 2x−44=x+2
i.e., x=46
Therefore ,
Present age of man=46 years
And present age of his son =46−24=22 years
mausi
Books=65+50=>115
Prices=1150+920=>2070
2070/115
18
FYI