Adventure Technologies Interview Questions, Process, and Tips

15a=45

the sum of first 4 primes numbers =2+3+5+7 =>17

Matches played: 60.
Matches won: 30% of 60 => (60*(30/100)) = 18 matches.
Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
20 / 62 = 0.3225806451612903
21 / 63 = 0.3333333333333333
22 / 64 = 0.34375
…
…
…
…
Similarly,
41 / 83 = 0.4939759036144578
42 / 84 = 0.5

So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.

B will use 8days to work

Solution:

As given, we have,

The cost of one pen = 36 Rs.

So, the cost of 15 pens = 36 × 15 = 540 Rs.

The cost of one book = 45 Rs.

So, the cost of 12 books = 45 × 12 = 540 Rs.

The cost of one pencil = 8 Rs.

So, the cost of 10 pencils = 8 × 10 = 80 Rs.

Now,

the cost of each eraser is 40 Rs. less than the combined costs of pen and pencil.

So,

Combined costs of pen and pencil = 36 + 8 = 44 Rs.

Cost of one eraser = 44 – 40 = 4 Rs.

So, the cost of 5 erasers = 4 × 5 = 20 Rs.

Hence,

The total amount spent is

Hence, the total amount spent is 1180 Rs.

Rs.265.80

area is doubled.
actual area = 1/2 bh
after increase area = 1/2 *4b* h /2
=bh
1/2 *bh *2 = bh
therefore area is doubled

F – Murderer
G – Victim
H – Judge
M – Police
C – Witness
W – Hangman

Total distance to cover = 132 +110 = 242m
Speed = 72kn/hr = 20m/s
time = 242/20 = 12.1 sec.

when know that 13 is factor of 39 so it will also not be able to divide it differently. so the remainder will be same 20 but as we know that 20 is greater then 13 so we can divide it once again and in the casE of 13 the remainder will be 20-13=7

Because from there i can do more and learned more too

A. Tea

only if the results are greater than my input

Had is correct ! Anil went in right direction but ended up
with wrong answers
Soln: B lied ( see anil’s comment ) which implies B has not
stolen mule. So B could steal camel or sheep.
1) Lets assume B stole camel.
In that case, A lies ( refer – A says “B had stolen sheep”
), which implies A had stolen sheep ( becoz a lier cant
steal mule ). So A->sheep B->camel C->mule. But this cant
happen because C cant lie ( refer – C says ” B had stolen
mule” ).
2) Lets assume B stole sheep.
In that case, A is true ( refer – A says “B had stolen
sheep” ), which implies A had stolen mule. So A->Mule
B->Sheep C->camel. Here C lies ( refer – C says ” B had
stolen mule” )
SO ANS: answer A- mule, B-sheep, C camel

let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer

88